Using spread with findIndex
Today I learned that it’s possible, and fairly easy to locate a single unique item in an array, remove it, and return a new array all without side effects. I’m going to walk you through the process using a hypothetical example.
Lets say that we’re developers working at a parking garage (extremely glamorous and exciting). The parking garage owner has a fully automated system that adds cars to the inventory, and assigns them a unique id. Essentially we’ll be working with an array filled with “car” objects.
let garage = [
{id: 529, make: 'Jeep', model: 'Cherokee'},
{id: 700, make: 'Ferrari', model: 'Laferrari'},
{id: 839, make: 'Subaru,' model: 'STI'},
{id: 912, make: 'Buick,' model: 'Continental'},
{id: 43, make: 'Tesla,' model: 'Model 3'}
];
The garage owner wants us to create a simple function that updates the state of the garage (it’s inventory) whenever a car leaves the facility. Luckily for us we can use findIndex
, and ...
(spread) along with the cars unique id
to get the job done easily. We’ll make a function called removeCar
, and pass it the id of the car, and the garage array.
Lets say we wanted to remove the car with the id of 912
from the garage
array. The first thing we would need to do is figure out where id 912 resides within the array. We’ll use findIndex
to loop though each element (car object) until it we find one that matches the provided id. Once the id is found, findIndex
will return the location where the match was made. Our car is at index 3
.
const removeCar = (carId, garage) => {
const carIndex = garage.findIndex(car => car.id === carId);
};
Once we have the index of the car that we’ll be removing, we use .slice
to find all of the cars before, and after it’s location in the array. Now that we have these “before”, and “after arrays, we can spread them into a new array literal and return it!
const removeCar = (carId, garage) => {
const carIndex = garage.findIndex(car => car.id === carId);
const carsBeforeIndex = garage.slice(0, carIndex);
const carsAfterIndex = garage.slice(carIndex + 1);
const newGarage = [...carsBeforeIndex, ...carsAfterIndex];
return newGarage;
};
This function should satisfy the requirements of our garage owner, and keep us happily employed.
let updatedGarage = removeCar(912, garage);
console.log(updatedGarage);
// {id: 529, make: 'Jeep', model: 'Cherokee'},
// {id: 700, make: 'Ferrari', model: 'Laferrari'},
// {id: 839, make: 'Subaru,' model: 'STI'},
// {id: 43, make: 'Tesla,' model: 'Model 3'}